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Data sharing btwn 2 tasks - Best Design?

Posted by jinx on May 14, 2010
I have two tasks A and B and I am looking for the best design mechanism using queues and/or semaphores to allow A to query B and then retrieve the data from B. Do you have a better method of doing this? The design I came up with is as follows:

I will first create a semaphore between A->B and a queue between B->A;

1. When A needs data, it will release the semaphore and then block on the queue from B->A.
2. B, that was blocking on the semaphore, will unblock, and then post the data on to the queue B->A.
3. A that was blocking on the queue will then unblock and then retrieve the data from the queue to allow further processing.

Is this the best way of doing it, or is there a better way?


RE: Data sharing btwn 2 tasks - Best Design?

Posted by Richard Damon on May 15, 2010
That method would work, my one thought is that if the tasks are really interlocked like this so only one of them is active at a time, what keeps you from combining them into a single task.

your method is basically

void taska(void* p) {
signal sema
pop data from queue
processing A
void taskb(void* p) {
wait for sema
processing B
push data to queue

And this can generally be replaced with:

void task(void *p){
while(1) {
processing B
processing A

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