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a way to execute one-time function with delay

Posted by rgavrilov on January 20, 2011
I understand I can do it with using CreateTask function.
Still, is there a light version to just execute a task once, without a need to clean it up? Something like:
void myTask(void *) { ... }
ExecuteOnceDelayed(myTask, a_parameter, a_delay_ms);


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