Question

### Gauthmathier5042

Grade 10 · 2021-01-10

\sum\limits _{n=0}^{\infty}\dfrac {3^{n}}{4^{n+1}} （ ）

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Answer

4.8(715) votes

### Gauthmathier5799

Grade 10 · 2021-01-10

Answer

A

Explanation

The series \dfrac {1}{4}+\dfrac {3}{16}+\dfrac {9}{64}+\cdots is geometric with a=\dfrac {1}{4} and r=\dfrac {3}{4}; it converges to \dfrac {\frac {1}{4}}{1-\frac {3}{4}}.

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